Simplification Or Other Simple Results

     
https://math.stackexchange.com/questions/254150/if-x-y-are-odd-integers-a-b-and-c-such-that-a4-b4-c4-argue-that
Hint: Suppose to the contrary that a & b are not relatively prime. Let phường a common prime divisor of a & b. Show that p must divide c. Remark: We vì not need anything about ...

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a4b4-c4 Final result : (a2b2 + c2) • (ab + c) • (ab - c) Step by step solution : Step 1 :Trying to lớn factor as a Difference of Squares : 1.1 Factoring: a4b4-c4 Theory : A difference of two ...
a4n-225b4 Final result : a4n - 225b4 Step by step solution : Step 1 :Equation at the over of step 1 : ((a4) • n) - (32•52b4) Step 2 :Trying to lớn factor as a Difference of Squares : 2.1 ...

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f(alpha)=0 implies that alpha f(alpha)=0. So, alpha^4-6alpha^3+14alpha^2-frac413alpha=0 We have similar results for eta & gamma. So, alpha^4+eta^4+gamma^4=6(alpha^3+eta^3+gamma^3)-14(alpha^2+eta^2+gamma^2)+frac413(alpha+eta+gamma)
https://www.quora.com/How-would-you-show-that-the-equation-a-4+b-4-c-4-has-no-nonzero-integer-solutions
The standard solution lớn this is a classic example of the ``method of infinite descent”, first formulated by Pierre de Fermat - Wikipedia. The proof I present here is one of the standard ...

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A systematic way doing this is using Newton's identifites . Let p_k = a^k + b^k + c^k for k = 1, 2, 3, 4 và eginalign s_1 &= a + b + c\ s_2 &= ab+bc+ca\ s_3 &= abc endalign be the ...
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left< eginarray l l 2 & 3 \ 5 & 4 endarray ight> left< eginarray l l l 2 & 0 và 3 \ -1 và 1 và 5 endarray ight>
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