Math Scene

The equation "sin (x) + cos (x) = 0" has only one solution mix "$x=frac3pi 4+pi n$".

Bạn đang xem: Math scene

Why it has not solution phối "$x=frac7pi 4+pi n$"? Although it satisfy the equation.

Please help quickly.


The equation is equivalent to$$ an x=-1$$ since the two functions $cos$ và $sin$ don"t vanish together so we find$$xequivfrac3pi4mod pi$$

A solution mix is a phối of points that satisfies a given equation. A given equation will have only one solution set. That set can have many descriptions. $frac 3pi4+npi$ is one mô tả tìm kiếm of the solution mix for this equation. $frac 7pi4+mpi$ is another description of the same set.

Xem thêm: Cách Ẩn Hiện Thanh Công Cụ Trong Excel Dành Cho Mọi Phiên Bản


Note that$$frac7pi4 + npi = left(1 + frac34 ight)pi + npi = frac3pi4 + (n+1)pi,$$so you are naming the same mix of solutions but with a different indexing system.


Thanks for contributing an answer to Stack Exchange!

Please be sure to answer the question. Provide details & share your research!

But avoid

Asking for help, clarification, or responding lớn other answers.Making statements based on opinion; back them up with references or personal experience.

Use to lớn format equations. reference.

Xem thêm: Bà Linh Tá Hỏa Phát Hiện Trinh Có Thai Với Chú Quang, Gạo Nếp Gạo Tẻ Tập 73

To learn more, see our tips on writing great answers.

Post Your Answer Discard

By clicking “Post Your Answer”, you agree lớn our terms of service, privacy policy & cookie policy

Find the smallest positive number $p$ for which the equation $cos(psin x)=sin(p cos x)$ has a solution $xin<0,2pi>.$
How prove this equation has only one solution $cos(2x)+cosxcdotcos(sqrt(pi-3x)(pi+x))=0$
If the equation $sin^2x-asin x+b=0$ has only one solution in $(0,pi)$, then what is the range of $b$?
For which value of $t in R$ the equation has exactly one solution : $x^2 + frac1sqrtcos t2x + frac1sin t = 2sqrt2$

Site design / hình ảnh sản phẩm © 2022 Stack Exchange Inc; user contributions licensed under CC BY-SA. Rev2022.11.18.43041

Your privacy

By clicking “Accept all cookies”, you agree Stack Exchange can store cookies on your device và disclose information in accordance with our Cookie Policy.