Solve the quadratic equation 12 = x^2 + x by factoring

     
Factor the expression by grouping. First, the expression needs to be rewritten as x^2+ax+bx-12. To find a và b, phối up a system khổng lồ be solved.

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Since ab is negative, a & b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. Các mục all such integer pairs that give hàng hóa -12.
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(x2-x-12) Final result : (x + 3) • (x - 4) Step by step solution : Step 1 :Trying to lớn factor by splitting the middle term 1.1 Factoring x2-x-12 The first term is, x2 its coefficient is ...
6x2-x-12 Final result : (2x - 3) • (3x + 4) Step by step solution : Step 1 :Equation at the over of step 1 : ((2•3x2) - x) - 12 Step 2 :Trying lớn factor by splitting the middle term ...
2x2-x-1 Final result : (x - 1) • (2x + 1) Step by step solution : Step 1 :Equation at the kết thúc of step 1 : (2x2 - x) - 1 Step 2 :Trying khổng lồ factor by splitting the middle term ...
3x2-x-1 Final result : 3x2 - x - 1 Step by step solution : Step 1 :Equation at the over of step 1 : (3x2 - x) - 1 Step 2 :Trying lớn factor by splitting the middle term 2.1 Factoring ...
6x2-x-1 Final result : (2x - 1) • (3x + 1) Step by step solution : Step 1 :Equation at the end of step 1 : ((2•3x2) - x) - 1 Step 2 :Trying to factor by splitting the middle term ...

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x2-x-18 Final result : x2 - x - 18 Step by step solution : Step 1 :Trying to factor by splitting the middle term 1.1 Factoring x2-x-18 The first term is, x2 its coefficient is 1 . The ...
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Factor the expression by grouping. First, the expression needs to lớn be rewritten as x^2+ax+bx-12. Lớn find a và b, set up a system khổng lồ be solved.
Since ab is negative, a và b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. List all such integer pairs that give sản phẩm -12.
Quadratic polynomial can be factored using the transformation ax^2+bx+c=aleft(x-x_1 ight)left(x-x_2 ight), where x_1 và x_2 are the solutions of the quadratic equation ax^2+bx+c=0.
All equations of the size ax^2+bx+c=0 can be solved using the quadratic formula: frac-b±sqrtb^2-4ac2a. The quadratic formula gives two solutions, one when ± is addition & one when it is subtraction.

Xem thêm: If A2+B2+C2−Ab−Bc−Ca=0, Prove That A=B=C, How To Prove A2+B2+C2≥Ab+Bc+Ca


Factor the original expression using ax^2+bx+c=aleft(x-x_1 ight)left(x-x_2 ight). Substitute 4 for x_1 và -3 for x_2.
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