# Triển khai: a) x1^3 + x2^3; b) x1/x2 + x2/x1

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f(x) = x^2 - 5x + 6

x1 and x2 are solution

We need khổng lồ determine the value of x1^3 + x2^3

From viete"s rule, we know that:

x1+ x2 = -b/a = 5.........(1)

x1*x2 = c/a = 6...........(2)

But f(x1) = f(x2) =0

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f(x) = x^2 - 5x + 6

x1 & x2 are solution

We need khổng lồ determine the value of x1^3 + x2^3

From viete"s rule, we know that:

x1+ x2 = -b/a = 5.........(1)

x1*x2 = c/a = 6...........(2)

But f(x1) = f(x2) =0

Multiply 3 by x1 & (4) by x2

= 5<(x1+x2)^2 - 2x1*x2> - 6(x1+x2)

= 5(5^2) - 5(2*6) - 6(5)

= 125 - 60 - 30

=125 - 90 = 35

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